Please corcorrespond to twain POST1: and POST2: in at meanest 200 say each.
Initial post that twain POST1: and POST2: are corresponding to.
Consider the aftercited two offices:
F(m): The mediocre region in Fahrenheit during month (m) of the year.
C(f): The transmutation formula to compute the region in Celsius grounded on the region in Fahrenheit (f).
For this argument, your work is as follows:
Calculate (C ∘ F) for the month of your excellent.
Discuss the significance of the office (C ∘ F)(m).
How does the mixture of offices in ability (a) and (b) assimilate to (F ∘ C)(m)? Are they the selfsame?
The month I conquer use to compute conquer be F(August)=84.
In this in we are using two public offices to effect desired outputs. These are offices accordingly for entire input there is barely one output.
a) C(F)=5/9*(F-32)= C(84)=5/9*(84-32)= 28.89
b) (C ∘ F)(m) is used to portray the office that transforms F(m) from a mediocre region in Fahrenheit to an mediocre region in Celsius. In the overhead in F(August)=84 so we can represent the appreciate of F to meet an equipollent output in Celsius.
c) (F ∘C)(m) would be used to transform the Mediocre region in Celsius to Mediocre region in Fahrenheit. This transmutation would need a public appreciate of C(m). That appreciate would be an input into the office F(C).
For this in, I chose to compute by origin month of February averaging 43 degrees Fahrenheit. Using c(f) = 5/9 (f-32)
A) The region in Celsius is computed as:
c(43) = 5/9 (43-32)
=6.1 degrees Celsius
B) The office (C ∘ F)(m) is to admit the mediocre region, in Fahrenheit, from the months in a year and transform this into Celsius.
C) (C ∘ F) (m) would be divergent from (F ∘ C) (m). While (C ∘ F) (m) gives the mediocre region of a feature month in Celsius, (F ∘ C) (m) transforms visa versa.