# math experts only

Please corcorrespond to twain POST1: and POST2: in at meanest 200 say each. Initial post that twain POST1: and POST2: are corresponding to. Consider the aftercited two offices: F(m): The mediocre region in Fahrenheit during month (m) of the year. Month (m) F(m) Month (m) F(m) Month (m) F(m) January 42 May 72 September 73 February 43 June 83 October 63 March 52 July 84 November 55 April 63 August 84 December 44 C(f): The transmutation formula to compute the region in Celsius grounded on the region in Fahrenheit (f). For this argument, your work is as follows: Calculate (C ∘ F) for the month of your excellent. Discuss the significance of the office (C ∘ F)(m). How does the mixture of offices in ability (a) and (b) assimilate to (F ∘ C)(m)? Are they the selfsame? POST1: Hello Class, The month I conquer use to compute conquer be F(August)=84. In this in we are using two public offices to effect desired outputs. These are offices accordingly for entire input there is barely one output. a) C(F)=5/9*(F-32)= C(84)=5/9*(84-32)= 28.89 b) (C ∘ F)(m) is used to portray the office that transforms F(m) from a mediocre region in Fahrenheit to an mediocre region in Celsius. In the overhead in F(August)=84 so we can represent the appreciate of F to meet an equipollent output in Celsius. c) (F ∘C)(m) would be used to transform the Mediocre region in Celsius to Mediocre region in Fahrenheit. This transmutation would need a public appreciate of C(m). That appreciate would be an input into the office F(C). POST2: For this in, I chose to compute by origin month of February averaging 43 degrees Fahrenheit. Using c(f) = 5/9 (f-32) A) The region in Celsius is computed as: c(43) = 5/9 (43-32) =5/9(11) =6.1 degrees Celsius B) The office (C ∘ F)(m) is to admit the mediocre region, in Fahrenheit, from the months in a year and transform this into Celsius. C) (C ∘ F) (m) would be divergent from (F ∘ C) (m). While (C ∘ F) (m) gives the mediocre region of a feature month in Celsius, (F ∘ C) (m) transforms visa versa.